Posted by Anonymous on Thursday, October 8, 2009 at 10:56pm.
y=mx+c
m= -1/6
y=-(1/6)x+c
The point (-6,9/7) must be on that line: use it to find c by plugging in x and y like
9/7=-(1/6)(-6)+c
So what's c?
So now we have the equation of the line, we need the value of the point on that line where x=12. Plug in 12 instead of x in the equation and work out what y must be.
18y+2x-9=0
we need to write as y=mx+c
18y+2x-9=0
move everything but y to the RHS:
18y=-2x+9
y=(-2/18)x+9/18
which you can simplify a bit.
You can do the other yourself the same way.
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