Posted by blair on Thursday, October 8, 2009 at 10:51pm.
You have three motions to consider.
Phase 1: powered by engine
With initial velocity of v0=80.8 m/s
it slows down due to gravity until a height of S=920 m. and an acceleration of a=3.9 m/s².
THe governing equation is
S = v0*t + (1/2)a*t²
Solve for t.
The velocity at the end of this phase is
v1=v0+a*t
Phase 2: deceleration until maximum height is reached, at which time velocity = 0.
Time to reach maximum height
t1 = v1/g
Additional height travelled:
S1=v1*t1 +(1/2)(-g)t1²
Phase 3: Free fall from maximum height S+S1
Use the usual equations to calculate the velocity and time
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