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August 29, 2014

August 29, 2014

Posted by **SC** on Thursday, October 8, 2009 at 9:06pm.

Year Seattle Port Townsend

1970 $38000 $8400

1990 $175000 $168400

(a) When will the average sales price in seattle and port t. be equal and what is this price?

(b)When will the average sales price in port t. be $15000 less than seattle sales price? What are the two sales prices at this time?

I need help setting up the equations for these two questions.

i found the linear model relating to this question

seattle is :

y=6850(x-1970)+38000

port t:

y=7980(x-1970)+8400

- Math -
**Benevolent Ben**, Thursday, October 8, 2009 at 9:27pmThe linear equations are:

seattle: y=6580(x-1970)+38000

port t: y=8000(x-1970)+8400 <---you made an arithmetic error in calculating the slope for this one

1. To find when they will be equal just set the to equations equal to each other:

6580(x-1970)+38000=8000(x-1970)+8400

6580x-12962600+3800=8000x-15760000+8400

2792800=1420x

x=1966.76

1966

2. Here you just take the port t equation, add 15000, and set that equal to the seattle equation

so

8000(x-1970)+8400+15000=6580(x-1970)+38000

do the algebra and you get: 1980.28

so 1980

the second part ask for the two sales prices during this time, so just plug our answer, 1980, back into the equations:

seattle: y=6580([1980.28-1970)+38000, y= $105,642.4

port t: y=y=8000(1980.28-1970)+8400, y= $90640

we can then check our answer by doing 105,642-90640=15002 which confirms that seattle at this time is 15000 more than port t. (the number is a tiny bit off because 1980.28 is rounded)

- Math -
**SC**, Thursday, October 8, 2009 at 9:41pmThanks for helping. What you explained to me makes sense. But i checked the back of the book and it said for (a) they will be equal in 1995 at $214,313.

so is (b) it said its 1982.70 Sea=$124,965. weird...

I going to try these problems out! and see what answers I get! thanks again.

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