What is the weight of a 76 kg astronaut on the Moon where the value of 'g' is only 17% the strength of 'g' on the Earth? (Answer should be expressed in N).

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To find the weight of the astronaut on the Moon, we can use the formula W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity.

First, we need to calculate the value of g on the Moon. Given that the strength of 'g' on the Moon is only 17% of the strength of 'g' on Earth, we can calculate it as: g_moon = 0.17 * g_earth.

Assuming the value of g on Earth is approximately 9.8 m/s², we can calculate g_moon as follows:
g_moon = 0.17 * 9.8 m/s² ≈ 1.666 m/s² (rounded to 3 decimal places).

Now, we can calculate the weight of the astronaut on the Moon using the formula W = mg:
W_moon = m * g_moon = 76 kg * 1.666 m/s².

Multiplying these values, we get:
W_moon ≈ 126.616 N.

Therefore, the weight of a 76 kg astronaut on the Moon, where the value of 'g' is only 17% the strength of 'g' on Earth, is approximately 126.616 Newtons.

His weight on earth is 76g N. where g is the acceleration due to gravity of 9.8 m/s²

The value of g is only 17% of that on earth, so his weight on the moon should be?
Post your answer if you would like a confirmation.