How do balance this equation K2S+CuSO4
Assuming they are both aqueous solutions, the results will be a dark brown precipitate of copper sulphide, CuS, so
K2S + CuSO4 -> K2SO4 + CuS
is already a balanced equation.
To balance the chemical equation K2S + CuSO4, we need to make sure that there is an equal number of each type of atom on both sides of the equation.
Here's how to balance the equation step by step:
1. Count the number of atoms on both sides of the equation. On the left side, we have 2 potassium (K), 1 sulfur (S), and 1 oxygen (O). On the right side, we have 1 copper (Cu), 1 sulfur (S), and 4 oxygen (O).
2. Start by balancing the elements that appear in only one molecule on each side of the equation. In this case, copper (Cu) and potassium (K) are the only elements that appear in only one molecule. So let's balance them first.
3. Balance the metals first. There are two potassium (K) atoms on the left, so we need to put a coefficient of 2 in front of K2S on the left side. This gives us 2K2S.
The equation now becomes:
2K2S + CuSO4
4. Next, balance the non-metals. There is 1 sulfur (S) atom on each side of the equation, so sulfur (S) is already balanced.
The equation now becomes:
2K2S + CuSO4
5. Finally, balance the oxygen (O) atoms. There are 4 oxygen (O) atoms in the compound CuSO4 on the right side. To balance the oxygen, put a coefficient of 2 in front of CuSO4 on the right side.
The final balanced equation is:
2K2S + CuSO4 -> K2SO4 + CuS
In the balanced equation, we have 2 potassium sulfide (K2S) molecules reacting with 1 copper sulfate (CuSO4) molecule to produce 1 potassium sulfate (K2SO4) molecule and 1 copper sulfide (CuS) molecule.