Posted by Anonymous on Thursday, October 8, 2009 at 2:07pm.
Gone fishing. Debbie traveled by boat 5 miles upstream to
fish in her favorite spot. Because of the 4mph current, it
took her 20 minutes longer to get there than to return. How
fast will her boat go in still water

algebra  MathMate, Thursday, October 8, 2009 at 3:43pm
Distance = D = 5 miles
Still water speed = S
current speed = 4 m.p.h.
Time to go upstream,T1 = 5/(S4)
Time to go downstream, T2 = 5/(S+4)
Difference,
T1T2 = 20/60 hour
Can you take it from here?
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