If a box contains 4 red poker chips and 3 blue. What is the probability that all 3 will be red if we randomly select each chip with replacement?

Woould it be 4/7*4/7*4/7 because there are 4 red or would it 3/7* 3/7*3/7 because they only want 3 of the 4?

Since you are replacing the chip, each new event is the same all over again.

Even though you don't say so, I will assume you are picking the chip 3 times.
so it would of course be (4/7)(4/7)(4/7)

To calculate the probability that all three chips drawn will be red, we need to consider the scenario when all three red chips are drawn out of a total of seven chips (4 red and 3 blue).

Since we are drawing with replacement, the number of red chips remains the same for each draw. Therefore, the probability of drawing a red chip on each selection is still 4/7.

To calculate the probability of all three red chips being drawn, we multiply the probability of drawing a red chip on each selection together.

So, the correct calculation would be:
(4/7) * (4/7) * (4/7) = 64/343.

Thus, the probability that all three chips will be red is 64/343.