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How many 3 digit odd numbers can be formed with the digits 1 through 9, if no digits is repeated in any number?

  • probability - ,

    Odd digits available
    = n({1,3,5,7,9})
    = 5
    Numer of digits to be formed per number
    = 3
    Number of choices for first digit = 5
    See previous question for methodology.

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