Posted by **Sharon** on Wednesday, October 7, 2009 at 11:03pm.

How many 3 digit odd numbers can be formed with the digits 1 thru 9, if no digits is repeated in any number?

- probability -
**MathMate**, Wednesday, October 7, 2009 at 11:06pm
Odd digits available

= n({1,3,5,7,9})

= 5

Numer of digits to be formed per number

= 3

Number of choices for first digit = 5

....

See previous question for methodology.

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