Posted by Sharon on Wednesday, October 7, 2009 at 11:03pm.
How many 3 digit odd numbers can be formed with the digits 1 through 9, if no digits is repeated in any number?

probability  MathMate, Wednesday, October 7, 2009 at 11:06pm
Odd digits available
= n({1,3,5,7,9})
= 5
Numer of digits to be formed per number
= 3
Number of choices for first digit = 5
....
See previous question for methodology.
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