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Posted by on Wednesday, October 7, 2009 at 10:31pm.

I am trying to find the inverse of matrix A but I don't know how to do it with sin and cos. Please help.

A=6e3tsin(6t) −6e4tcos(6t)
−5e3tcos(6t) −5e4tsin(6t)


then A−1=

  • linear algebra - , Wednesday, October 7, 2009 at 10:52pm

    The inverse of a 2x2 can be done as follows:

    For matrix, A=
    |a b|
    |c d|
    The inverse A-1=
    |d -b|
    |-c a| / (ad-bc)

    For example:
    If A=
    |4 5|
    |6 7|
    A-1 =
    |7 -5|
    |-6 4| / (28-30)
    =
    |-3.5 2.5|
    |3 -2|

    Check:
    |4 5| |-3.5 2.5|
    |6 7| |3 -2|
    =
    |1 0|
    |0 1|

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