Two children playing on the beach are pulling on an inner tube. One exerts a force of 45 N [N]. The other exerts a force of 60 N [SW]. What is the net force acting on the tube?

see below.

Okay but is 42 the answer ?

15N beause you subtract 60-45

the Earth (mass = 5.98 × 1024 kg) moving with an orbital speed equal to 2.98 × 104 m/s.

146216

To find the net force acting on the tube, we need to combine the individual forces acting on it. In this case, we have one force of 45 N acting towards the north (upward) and another force of 60 N acting towards the southwest.

To combine these forces, we can use vector addition. The force in the north direction is positive, while the force in the southwest direction is negative.

First, let's break down the 60 N force into its north (vertical) and west (horizontal) components. To do this, we can use trigonometry. Since the force is acting towards the southwest, we can split it into a force directed south (downward) and a force directed east (to the right).

The southward force (vertical component) can be found by multiplying the magnitude of the force (60 N) by the sine of the angle it makes with the horizontal axis. Assuming the angle is 45 degrees, the southward force would be 60 N * sin(45°) = 42.4 N [S].

The eastward force (horizontal component) can be found by multiplying the magnitude of the force (60 N) by the cosine of the angle it makes with the horizontal axis. The eastward force would be 60 N * cos(45°) = 42.4 N [E].

Now, we have three forces: 45 N [N], 42.4 N [S], and 42.4 N [E].

To compute the net force, we add up the northward force and subtract the southward and eastward forces since they act in the opposite directions.

Net force (vertical) = 45 N - 42.4 N = 2.6 N [N]
Net force (horizontal) = 42.4 N [E]

Therefore, the net force acting on the inner tube is 2.6 N [N] vertically (northward) and 42.4 N [E] horizontally.