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November 28, 2014

November 28, 2014

Posted by **jay** on Wednesday, October 7, 2009 at 7:46pm.

The shorter leg of a 30°–60°–90° triangle is 12. What are the lengths of the longer leg and the hypotenuse, to the nearest tenth?

- math -
**jim**, Wednesday, October 7, 2009 at 8:53pmFirst, draw your triangle so you can see what you're doing. The short side, 12, will be opposite the small angle, 30.

We know that the sin of an angle = opposite over hypotenuse. The angle is 30, and we can look up sin(30)=0.5.

So opposite (which we know is 12) over hypotenuse = 1/2.

12/hypotenuse = 1/2

hypotenuse = 24.

Now we can get the final, adjacent, side in either of two ways:

1. Pythagoras: 12^2 + adjacent^2 = 24^2

or

2. use the definition of cos = adjacent over hypotenuse. We can look up cos(30) = sqrt(3)/2 or .8660. So:

adjacent/24 = .8660

and mutiply across from there.

- math -
**Reiny**, Wednesday, October 7, 2009 at 9:52pmThe sides of the 30-60-90 triangel are in the ratio of 1:√3:2

your triangle is 12:a:b

so 1/12 = √3/a

a = 12√3

and 1/12 = 2/b

b = 24

the other two sides are 12√3 and 24

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