Posted by **Claudizzle** on Wednesday, October 7, 2009 at 6:02pm.

One car traveling at 55mi/h left a certai place 3h later than another car. The second car was traveling in the same direction at 40 mi/h. Inhow many hours ill the faster car ovrtae the other?

My work:

55(t-3) = 40t]

55t-165 = 40t

-55t -55t

-165 = -15t

/-15 /-15

11 = t

9 = t-3

I keep getting this answer, and my teacher told me it's worng, but I can't find what I'm doing wrong. Please HELP!!!

- HELPPPP!!!! -
**bobpursley**, Wednesday, October 7, 2009 at 6:11pm
Since when is 11-3=9?

So we all have Duh moments.

Good work almost.

- HELPPPP!!!! -
**Ms. Sue**, Wednesday, October 7, 2009 at 6:14pm
The wording of your problem is confusing.

The first car (car A) traveled at 40 mph and left three hours earlier than the second car (Car B).

Car A had traveled 120 miles when Car B left.

After 4 hours, A went 160 miles. B went 55 miles

5 hours: A went 200 mi. B went 110 mi.

6 hours: A went 240 mi. B went 165 mi.

7 hours: A went 280 mi. B went 220 mi.

8 hours: A went 320 mi. B went 275 mi.

Continue this chart to find your answer.

Then go back over your equation to find your error.

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