Posted by Claudizzle on .
One car traveling at 55mi/h left a certai place 3h later than another car. The second car was traveling in the same direction at 40 mi/h. Inhow many hours ill the faster car ovrtae the other?
55(t-3) = 40t]
55t-165 = 40t
-165 = -15t
11 = t
9 = t-3
I keep getting this answer, and my teacher told me it's worng, but I can't find what I'm doing wrong. Please HELP!!!
Since when is 11-3=9?
So we all have Duh moments.
Good work almost.
The wording of your problem is confusing.
The first car (car A) traveled at 40 mph and left three hours earlier than the second car (Car B).
Car A had traveled 120 miles when Car B left.
After 4 hours, A went 160 miles. B went 55 miles
5 hours: A went 200 mi. B went 110 mi.
6 hours: A went 240 mi. B went 165 mi.
7 hours: A went 280 mi. B went 220 mi.
8 hours: A went 320 mi. B went 275 mi.
Continue this chart to find your answer.
Then go back over your equation to find your error.