Posted by Claudizzle on Wednesday, October 7, 2009 at 6:02pm.
One car traveling at 55mi/h left a certai place 3h later than another car. The second car was traveling in the same direction at 40 mi/h. Inhow many hours ill the faster car ovrtae the other?
My work:
55(t3) = 40t]
55t165 = 40t
55t 55t
165 = 15t
/15 /15
11 = t
9 = t3
I keep getting this answer, and my teacher told me it's worng, but I can't find what I'm doing wrong. Please HELP!!!

HELPPPP!!!!  bobpursley, Wednesday, October 7, 2009 at 6:11pm
Since when is 113=9?
So we all have Duh moments.
Good work almost.

HELPPPP!!!!  Ms. Sue, Wednesday, October 7, 2009 at 6:14pm
The wording of your problem is confusing.
The first car (car A) traveled at 40 mph and left three hours earlier than the second car (Car B).
Car A had traveled 120 miles when Car B left.
After 4 hours, A went 160 miles. B went 55 miles
5 hours: A went 200 mi. B went 110 mi.
6 hours: A went 240 mi. B went 165 mi.
7 hours: A went 280 mi. B went 220 mi.
8 hours: A went 320 mi. B went 275 mi.
Continue this chart to find your answer.
Then go back over your equation to find your error.
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