One car traveling at 55mi/h left a certai place 3h later than another car. The second car was traveling in the same direction at 40 mi/h. Inhow many hours ill the faster car ovrtae the other?
My work:
55(t-3) = 40t]
55t-165 = 40t
-55t -55t
-165 = -15t
/-15 /-15
11 = t
9 = t-3
I keep getting this answer, and my teacher told me it's worng, but I can't find what I'm doing wrong. Please HELP!!!
11-3=8, at least here in Texas.
13×+5×=3
To solve this problem, you are on the right track with setting up the equation:
55(t - 3) = 40t
However, it seems like there might be a small mistake in applying the distributive property. Let's go through the steps again:
Step 1: Distribute 55 to both terms inside the parentheses.
55t - 3 * 55 = 40t
Step 2: Simplify.
55t - 165 = 40t
Now, let's solve for t by isolating the variable on one side of the equation:
Step 3: Subtract 40t from both sides.
55t - 40t - 165 = 0
15t - 165 = 0
Step 4: Add 165 to both sides.
15t = 165
Step 5: Divide both sides by 15.
t = 11
Therefore, the correct answer is t = 11 hours. This means the faster car will overtake the slower car after 11 hours.