Posted by Kalen on Wednesday, October 7, 2009 at 12:45pm.
Since you mentioned 0.63 m/s, but the mass of the object is 100 g, there is uncertainty as to what unit is being used. You may want to include units in your future questions.
There are two stages of the motion of the object.
Stage 1: movement on the table, and
stage 2: free fall with horizontal velocity.
I will tackle stage 2 first, since all data are given.
First, consider vertical movement.
v0=0 m/s
a=-9.8 m/s²
Vertical distance,
Sv = v0*t + (1/2)at² = -1.5
Solving for t
t=sqrt(2Sv/a)
During this time, the object has travelled Sh metres.
Thus horizontal velocity, Vh
= Sh/t
For the stage 1 motions,
v0 = initial velocity, to be found
vh = final velocity, found above
acceleration = -μg due to friction
Distance, S=2.9 m
Use
vh²-v0²=2aS to solve for v0.
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