Blocks with masses of 1kg , 4kg , and 6kg are lined up in a row on a frictionless table. All three are pushed forward by a 50N force applied to the 1kg block.

How much force does the 4kg block exert on the 6kg block?
How much force does the 4kg block exert on the 1kg block?

To find the force that the 4kg block exerts on the 6kg block, we need to understand that when two objects interact (in this case, the 4kg and 6kg blocks), the force exerted by one block on the other will be equal in magnitude but opposite in direction.

Given that the 1kg block is pushing the 4kg block with a force of 50N, and the 4kg block is in contact with the 6kg block, we can conclude that the force exerted by the 4kg block on the 6kg block is also 50N in magnitude, but in the opposite direction. Therefore, the force exerted by the 4kg block on the 6kg block is -50N.

To find the force that the 4kg block exerts on the 1kg block, we can use Newton's third law, which states that for every action, there is an equal and opposite reaction.

Since the 4kg block is pushing on the 1kg block with a force of 50N, the 1kg block will push back on the 4kg block with an equal force of 50N in the opposite direction. Therefore, the force exerted by the 4kg block on the 1kg block is 50N.

To answer these questions, we need to understand Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.

When the 50N force is applied to the 1kg block, it will accelerate in the forward direction. Due to the lack of friction, the force will be transferred to the 4kg and 6kg blocks as well.

1. How much force does the 4kg block exert on the 6kg block?
Since the 4kg block is in direct contact with the 6kg block, the force exerted by the 4kg block will be the same as the force it experiences from the 1kg block and vice versa. According to Newton's Third Law, the force exerted by the 4kg block on the 6kg block will also be 50N.

2. How much force does the 4kg block exert on the 1kg block?
Again, according to Newton's Third Law, the force exerted by the 4kg block on the 1kg block will be equal and opposite to the force exerted by the 1kg block on the 4kg block. Therefore, the force exerted by the 4kg block on the 1kg block will also be 50N.

Would the force of the 4kg block acting on the 1kg block be the mass=4kg+6kg times the acceleration =50/11?

Draw free body diagrams and wqrite equations of motion for each block, including internal forces acting on the blocks that contact each other. remeber that action equals reaction. You will end up with four equations in four unknowns: three internal forces plus the acceleration. You can solve for them all.