Posted by badatmath on Wednesday, October 7, 2009 at 11:12am.
A longdistance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point
A) 8.616 mi
B) 10 mi
C) 7.616 mi
D) 4.472 mi
I think it is eaither A or C but not sure

math  Ms. Sue, Wednesday, October 7, 2009 at 11:19am
Using the Pythagorean Theorem, I found the distance to be 7.616 miles.
a^2 + b^2 = c^2
3^2 + 7^2 = c^2
9 + 49 = 58
square root of 58 = 7.616

math  Reiny, Wednesday, October 7, 2009 at 11:19am
simple case of using Pythagoras
d^2 = 3^2 + 7^2
d^2 = 58
d = √58 = 7.616

math  bobpursley, Wednesday, October 7, 2009 at 12:02pm
http://www.arcytech.org/java/pythagoras/history.html
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