Posted by **badatmath** on Wednesday, October 7, 2009 at 11:12am.

A long-distance runner runs 3 miles south and then 7 miles east. How far is the runner from the starting point

A) 8.616 mi

B) 10 mi

C) 7.616 mi

D) 4.472 mi

I think it is eaither A or C but not sure

- math -
**Ms. Sue**, Wednesday, October 7, 2009 at 11:19am
Using the Pythagorean Theorem, I found the distance to be 7.616 miles.

a^2 + b^2 = c^2

3^2 + 7^2 = c^2

9 + 49 = 58

square root of 58 = 7.616

- math -
**Reiny**, Wednesday, October 7, 2009 at 11:19am
simple case of using Pythagoras

d^2 = 3^2 + 7^2

d^2 = 58

d = √58 = 7.616

- math -
**bobpursley**, Wednesday, October 7, 2009 at 12:02pm
http://www.arcytech.org/java/pythagoras/history.html

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