1 SPOOF IS A SET OF ALL PURRS.
2 SPOOF CONTAINS AT LEAST TWO DISTINCT PURRS.
3 EVERY LILT IS A SET OF PURRS AND CONTAINS AT LEAST TWO DISTINCT PURRS.
4. IF A AND B ARE ANY TWO DISTINCT PURRS, THERE IS ONE AND ONLY ONE LILT THAT CONTAINS THEM.
5. NO LILT CONTAINS ALL THE PURRS.
SHOW THAT THE FOLLOWING STATEMNTS ARE TRUE.
1- THERE IS AT LEAST ONE LILT.
2- THERE ARE AT LEAST THREE PURRS.
3- THERE ARE AT LEAST THREE LILTS
That allcaps is a bit hard on the eyes. If you want people to read your message, do tone it down and type normally, please.
From 2) spoof contains at least two purrs. Call the first two A and B. From 4) there exists exactly one lilt containing them, therefore 1. is proved.
Call the lilt cntaining A and B L1.
From 5), there must exist a purr that is outside L1.
Therefore there must exist a third purr, therefore 2. is proved.
We now have a third purr; call it C.
I will leave it for you to prove that, given purrs A, B, and C, there must exist at least three lilts.
Ummm... if A and B are already taken then that's 1 lilt. And C is in one lilt so there are two lilts??? can you explain how you got three please=).
Each lilt contains at least one distinct pair.
There must be exactly one lilt containing each possible pair. Which axiom number is that?
We know that L1 contains {A, B}.
Write out the pairs you can make from A, B, C.
oooo thanks man
the sum of the ________ of a plane figure is called the perimeter.
thanks yall
To show that the statements are true, we can analyze the given information and use logical reasoning.
1. There is at least one LILT:
From statement 3, we know that every LILT is a set of PURRS and contains at least two distinct PURRS. Therefore, if we have at least two distinct PURRS, we can form a LILT. Since statement 2 states that SPOOF contains at least two distinct PURRS, we can conclude that there is at least one LILT.
2. There are at least three PURRS:
From statement 4, we know that if A and B are any two distinct PURRS, there is exactly one LILT that contains them. This means that for every pair of distinct PURRS, there is a unique LILT containing them. Since we need at least two distinct PURRS to form a LILT, we can conclude that there must be at least three PURRS present.
3. There are at least three LILTS:
To determine this, we need to consider the statements provided. Since statement 2 states that SPOOF contains at least two distinct PURRS, and statement 3 states that every LILT is a set of PURRS and contains at least two distinct PURRS, we can conclude that there is at least one LILT containing the two distinct PURRS in SPOOF. Furthermore, from statement 4, we know that for any two distinct PURRS, there is one and only one LILT that contains them. Therefore, we can conclude that there is another LILT not containing the first two PURRS. Hence, we have at least two LILTS. Finally, since statement 5 states that no LILT contains all the PURRS, we can conclude that there must be at least three LILTS, as there is one LILT with the first two PURRS, another LILT with the third distinct PURR, and a third LILT that does not contain any of the three distinct PURRS.
In summary:
1. There is at least one LILT.
2. There are at least three PURRS.
3. There are at least three LILTS.