Posted by Sanjna on Tuesday, October 6, 2009 at 5:26pm.
A 0.20kg ball on a string is whirled on a vertical circle at a constant speed. When the ball is at the three o'clock position, the string tension is 16 N. Find the tensions in the string when the ball is at twelve o'clock and at the six o'clock positions.
* Physics  bobpursley, Tuesday, October 6, 2009 at 4:52pm
at three oclock, Tension= mv^2/r
then at 12 oclock,
tension= mv^2/rmg
and at six...
tension= mv^2/r + mg
How do I solve for the r and the v?

Physics  bobpursley, Tuesday, October 6, 2009 at 5:28pm
YOu don't need it.
you know mv^2/r=16N 
Physics  Tucker, Sunday, September 30, 2012 at 8:55pm
Just sub some numbers in to make it work. For example... tension/mass (16/.2)=80. So 80 is equal to rv^2. so make v=10 m/s and r =.8 m so everything will work out. It stays the same throughout so you can 'make up' the numbers