Posted by Tierney on Tuesday, October 6, 2009 at 5:20pm.
Assume 100 g for the first part.
then you have 41.4 g of C, or xxx moles
then you have 3.47 g of H, or yyy moles H
and you have 55.1g of O, or zzz moles of O
Now, look at the xxxx,yyy, zzz numbers. Divide all of them by the LEAST number, you should be able to get a whole number ratio for the three elements.
That will give you the empirical formula.
Now, the mole mass is known:
molmass= 5.80/.050 g
divide the empirical formula mole mass into the known mole mass. That will give you a whole number ratio to multiply the subscripts in the empirical formula by. The result is the actual molecular formula.
I answered this below. It may not have been your post. If not, I'll post a link to the answer.
It WAS your post. Why are you posting the same question again. Didn't you look for the response?
http://www.jiskha.com/display.cgi?id=1254861796
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