Question

f(x) = sq.root(e^2x+1), then f'(0)=

a. -sq.root(2)/2
b. sq.root(2)/4
c. sq.root(2)/2
d. 1
e. sq.root(2)

Answer 1

f'=-.5(e^2x + 1)^-.5 * e^2x *2

f'(0)=- 1/sqrt(2)= - sqrt(2)/2

check that.