On an NBA team the two forwards measure 6'8" & 6'6" and the two grounds measure 6'0" & 5'9". how tall a center should they hire if they wish to have a starting team average height of at least 6'5" ?

(6'8 + 6'6 + 6,0 + 5,9 + x)/ 5

5’6

To determine how tall the center should be to achieve a starting team average height of at least 6'5", we need to find the total height of the four players and then divide it by the total number of players.

First, let's convert all the heights to inches for consistency.

The two forwards measure 6'8" and 6'6" respectively, which is equal to 80 inches and 78 inches.

The two guards measure 6'0" and 5'9", which is equal to 72 inches and 69 inches.

Next, we calculate the combined height of all four players:
Total height = 80 + 78 + 72 + 69 = 299 inches.

Since there are four players, we divide the total height by four to get the average height of the team:
Average height = 299 / 4 = 74.75 inches.

Now, we need to determine how tall the center should be to achieve an average height of at least 6'5", which is equal to 77 inches.

To find the height the center needs to have, we set up the following equation:
(299 + x) / 5 = 77.

Here, '299' represents the total height of the existing four players, 'x' represents the height of the center, and '5' represents the total number of players.

We can solve this equation by isolating 'x':
299 + x = 5 * 77,
x = (5 * 77) - 299,
x = 385 - 299,
x = 86.

Therefore, the center should be at least 86 inches tall to achieve a starting team average height of at least 6'5".