Two planes are 4,800 miles apart, and their speeds differ by 200 mph. They travel toward each other and meet in four hours. Find the speed of the slower plane. HELP!!!!!

F+S=distance/time

S+200+S=4800/4
solve for S, then solve for F

To find the speed of the slower plane, we can set up a system of equations and solve for the unknown variables.

Let's denote the speed of the slower plane as 'x' mph and the speed of the faster plane as 'x + 200' mph.

Since both planes travel towards each other, their combined speeds will add up, giving us the equation:

x + (x + 200) = 4800/4

Simplifying the equation, we get:

2x + 200 = 1200

Subtracting 200 from both sides, we have:

2x = 1000

Dividing both sides by 2, we get:

x = 500

Thus, the speed of the slower plane is 500 mph.