Posted by MAdason on Tuesday, October 6, 2009 at 9:58am.
Five forces act on an object: 1: 60 N at 90 degrees, 2: 40 N at 0 degrees, 3: 80 N at 270 degrees, 4: 40 N at 180 degrees, and 5: 50 N at 60 degrees. What is the magnitude and direction of the 6th froce that would produce equilibrium?

physics  drwls, Tuesday, October 6, 2009 at 10:12am
The vector sum of the six forces must be zero. Write that in the form of two equations (one each for the x and y components). Then solve for the unknown components of the sixth force.

physics  Teklu, Thursday, December 30, 2010 at 2:18am
At a point forces of 60N and 90N are acting and the angle between them is 60 degree. Determine the magnitude and the direction of their Resultant by graphical method

physics  Anonymous, Thursday, November 17, 2011 at 9:18pm
30 N

physics  Henry, Saturday, August 8, 2015 at 12:20pm
Fr = 60[90o] + 40[0o] + 80[270o] + 40[180] + 50[60o].
X=60*Cos90+40*Cos0+80*Cos270+40*Cos180+50*Cos60 = 0 + 40 + 0  40 + 25 = 25 N.
Y=60*sin90+40*sin0+80*sin270+50*sin60 =
60 + 0  80 + 0 + 43.3 = 23.3 N.
Fr = X+Yi = 25 + 23.3i.
Fe = 25  23.3i = 34.2N[43.2o+180] =
34.2N[223.2o].
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