Posted by Sela on Monday, October 5, 2009 at 9:15pm.
a=13m/s²
v = 0 + a*t1....(1)
t1+t2=90....(2)
S=0*t1+(1/2)a*(t1)² + v*t2....(3)
Express v and t2 in terms of t1 and solve for t1 using the third equation.
Find the velocity at the end of the acceleration.
v=13t1
distance1= 1/2 13 t1^2
distance2= velocity*time= 1/2 13 t1(90-t1)
t2 is 90 sec
5.3E3=1/2 13 t1^2+ 1/2 13 t1(90-t1)
do the algebra, solve for t1.
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