Posted by confused on Monday, October 5, 2009 at 9:01pm.
Find the equation of the ellipse with vertices at (1,3) and (5,3)and length of minor 4.

Algebra  Reiny, Monday, October 5, 2009 at 9:16pm
first find the centre, which would be the midpoint of the vertices,
it would be (2,3)
the length of the minor axis is 4, so b = 2
sofar we would would have
(x2)^2/a^2 + (y3)^2/4 = 1
but (5,3) lies on it, so
(52)^2/a^2 + (33)^2/4 = 1
9/a^2 = 1
a^2 = 9
final equation
(x2)^2/9 + (y3)^2/4 = 1

Algebra  confused, Monday, October 5, 2009 at 9:19pm
thanks!

Algebra  vero, Tuesday, October 6, 2009 at 9:50pm
8(16)
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