Posted by confused on .
Find the equation of the ellipse with vertices at (1,3) and (5,3)and length of minor 4.

Algebra 
Reiny,
first find the centre, which would be the midpoint of the vertices,
it would be (2,3)
the length of the minor axis is 4, so b = 2
sofar we would would have
(x2)^2/a^2 + (y3)^2/4 = 1
but (5,3) lies on it, so
(52)^2/a^2 + (33)^2/4 = 1
9/a^2 = 1
a^2 = 9
final equation
(x2)^2/9 + (y3)^2/4 = 1 
Algebra 
confused,
thanks!

Algebra 
vero,
8(16)