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Algebra

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Find the equation of the ellipse with vertices at (-1,3) and (5,3)and length of minor 4.

  • Algebra - ,

    first find the centre, which would be the midpoint of the vertices,
    it would be (2,3)
    the length of the minor axis is 4, so b = 2

    sofar we would would have
    (x-2)^2/a^2 + (y-3)^2/4 = 1
    but (5,3) lies on it, so
    (5-2)^2/a^2 + (3-3)^2/4 = 1
    9/a^2 = 1
    a^2 = 9

    final equation
    (x-2)^2/9 + (y-3)^2/4 = 1

  • Algebra - ,

    thanks!

  • Algebra - ,

    8(16)

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