A researcher interested in relationships developed a questionnaire that measures the degree of affection adult men feel for their fathers. She has found that for the general population the distribution is skewed to the right, the mean degree of affection is 60, and the standard deviation is 16. The researcher now is wondering if men who themselves have just become new fathers will score higher on the scale than men in general. She samples a group of 100 new fathers and finds that their mean is 64.5.
What is the variance on this questionnaire in the general population?
For a population with a standard deviation of ċ = 8, a score of X = 44 corresponds to z = -0.50. What is the population mean?
To find the variance on this questionnaire in the general population, we need to use the formula:
Variance = standard deviation^2
Given that the standard deviation of the general population is 16, we can calculate the variance as follows:
Variance = 16^2 = 256
Therefore, the variance on this questionnaire in the general population is 256.
To find the variance on the questionnaire in the general population, we need to use the standard deviation provided. Variance is the square of the standard deviation.
Given:
Mean degree of affection in the general population = 60
Standard deviation = 16
Variance = Standard deviation^2
Variance = 16^2 = 256
Therefore, the variance on this questionnaire in the general population is 256.
This sounds like a trick question.
If the standard deviation of the answer from the general population is 16, then the variance is σ2, which is 256.