Posted by Mary on Monday, October 5, 2009 at 12:36am.
I made an error - Why is the atmospheric pressure of 14.7 lb/in2)not added to the pressure of the tire gauge when computing the weight of the vehicle?
You can only get an approximate weight of the vehicle by multiplying the tire gauge pressure by the area of the tires in contact with the road.
It is appropriate to use the gauge, rather than the absolute, pressure in such calculations because atmospheric pressure acts on the entire exterior of the car except the road contact area. This has the effect of creating a buoyant force that equals the reduction in weight that you get by using the gauge pressure in the weight calculation.
Related Questions
Chemistry - How many moles of gas must be forced into a 4.8L tire to give it a ...
physics - A tire with an inner volume of 0.0250 m3 is filled with air at a gauge...
Physics - An automobile tire is inflated with air originally at 10.0°C and ...
physics - An automobile tire has a volume of 1.60 x 10-2 m3 and contains air at ...
thermal physics - An automobile tire has a volume of 1.60 x 10-2 m3 and contains...
Physics - An automobile tire contains a certain volume of air at 30 psig and 70...
physics - driving on a hot day causes tire pressure to rise. what is the ...
Physics - Suppose a large dump truck tire has a surface area of 26.3 m^2. If a ...
Physics - Suppose a large dump truck tire has a surface area of 26.3 m^2. If a ...
physics - You inflate your car tires to a gauge pressure of 2.43 atmospheres at ...
For Further Reading
