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January 30, 2015

January 30, 2015

Posted by **ester sanderson** on Sunday, October 4, 2009 at 11:13pm.

- statistics -
**MathMate**, Monday, October 5, 2009 at 9:32amA hypothesis related to the population proportion will be tested. In this case,

Theoretical proportion, π0 = 1/6,

number of observations, n = 60

Observed proportion, p = 9/n = 9/60

In the case where n>30, nπ0>5 and n(1-π0)>5, the normal distribution could be used as an approximation for the test of the null hypothesis, H0, where

H0 : the sample proportion, π = 1/6.

The sample standard error, σp

=sqrt(π0(1-π0)/n)

=sqrt((1/6)(5/6)/60)

=0.048

z=(p-π0)/σp

=(9/60-1/6)/0.048

=-0.347

critical z (α=0.05)=-1.645 (from the Normal distribution table).

Since -0.347 is greater than -1.645, the null hypothesis is not rejected at the 5% level of significance, i.e. there is no indication that the die is loaded.

- statistics -
**isaac**, Friday, January 4, 2013 at 12:32pmFind the chance that if you toss a pair of dice, you get 6 for the sum.

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