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March 29, 2017

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an adult 68 kg cheetah can accelerate from rest to 20.1 m/s (45 mph) in 2.0 s. Assuming constant acceleration, (a) find the net external force causing this acceleration. (b) where does the force come from? that is, what exerts the force on the cheetah?

  • Physics - ,

    a= deltav/time

    F=ma

    Doesn't the ground exert force on the cheta?

  • Physics - ,

    i don't get the first equation explain more please

  • Physics - ,

    acceleration= changeinvelocity/time.

  • Physics - ,

    should i be using the equation you wrote for finding the net EXTERNAL force??

  • Physics - ,

    Yes. That is the force accelerating the cheeta.

  • Physics - ,

    i got 1366.8 N and i'm asked to round to SF would it be 1.3*10^2?

  • Physics - ,

    a= 20.1m/s /2= 10.05m/s^2
    F= ma

    How did you get that number 1366?

    Now, rounding 1366.8 is not 1/3E2

    E2 is 100. But you have other errors that need to be corrected.

  • Physics - ,

    i corrected it and i got 683.4 N, does that sounds right? if yes, would it be 6.8E-1?

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