Posted by Adam on Sunday, October 4, 2009 at 7:37pm.
an adult 68 kg cheetah can accelerate from rest to 20.1 m/s (45 mph) in 2.0 s. Assuming constant acceleration, (a) find the net external force causing this acceleration. (b) where does the force come from? that is, what exerts the force on the cheetah?

Physics  bobpursley, Sunday, October 4, 2009 at 7:38pm
a= deltav/time
F=ma
Doesn't the ground exert force on the cheta?

Physics  Adam, Sunday, October 4, 2009 at 7:39pm
i don't get the first equation explain more please

Physics  bobpursley, Sunday, October 4, 2009 at 7:40pm
acceleration= changeinvelocity/time.

Physics  Adam, Sunday, October 4, 2009 at 7:44pm
should i be using the equation you wrote for finding the net EXTERNAL force??

Physics  bobpursley, Sunday, October 4, 2009 at 7:46pm
Yes. That is the force accelerating the cheeta.

Physics  Adam, Sunday, October 4, 2009 at 7:49pm
i got 1366.8 N and i'm asked to round to SF would it be 1.3*10^2?

Physics  bobpursley, Sunday, October 4, 2009 at 7:53pm
a= 20.1m/s /2= 10.05m/s^2
F= ma
How did you get that number 1366?
Now, rounding 1366.8 is not 1/3E2
E2 is 100. But you have other errors that need to be corrected.

Physics  Adam, Sunday, October 4, 2009 at 8:10pm
i corrected it and i got 683.4 N, does that sounds right? if yes, would it be 6.8E1?
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