Posted by **Adam** on Sunday, October 4, 2009 at 7:37pm.

an adult 68 kg cheetah can accelerate from rest to 20.1 m/s (45 mph) in 2.0 s. Assuming constant acceleration, (a) find the net external force causing this acceleration. (b) where does the force come from? that is, what exerts the force on the cheetah?

- Physics -
**bobpursley**, Sunday, October 4, 2009 at 7:38pm
a= deltav/time

F=ma

Doesn't the ground exert force on the cheta?

- Physics -
**Adam**, Sunday, October 4, 2009 at 7:39pm
i don't get the first equation explain more please

- Physics -
**bobpursley**, Sunday, October 4, 2009 at 7:40pm
acceleration= changeinvelocity/time.

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**Adam**, Sunday, October 4, 2009 at 7:44pm
should i be using the equation you wrote for finding the net EXTERNAL force??

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**bobpursley**, Sunday, October 4, 2009 at 7:46pm
Yes. That is the force accelerating the cheeta.

- Physics -
**Adam**, Sunday, October 4, 2009 at 7:49pm
i got 1366.8 N and i'm asked to round to SF would it be 1.3*10^2?

- Physics -
**bobpursley**, Sunday, October 4, 2009 at 7:53pm
a= 20.1m/s /2= 10.05m/s^2

F= ma

How did you get that number 1366?

Now, rounding 1366.8 is not 1/3E2

E2 is 100. But you have other errors that need to be corrected.

- Physics -
**Adam**, Sunday, October 4, 2009 at 8:10pm
i corrected it and i got 683.4 N, does that sounds right? if yes, would it be 6.8E-1?

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