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Homework Help Forum: Trig

Posted by Sarah on Sunday, October 4, 2009 at 5:29pm.

A line goes through points (23,-3) and (83,3). Find the equation of the line through these 2 points and the angle of incline (between the line and the x-axis).

  • Trig - Reiny, Sunday, October 4, 2009 at 5:44pm

    The slope of your line is 6/(6√3) = 1/√3
    Then, using the point (2√3,-3)

    y+3 = (1/√3)(x-2√3)
    cross-multiplying, expanding and then simplifying I got
    x - (√3)y = 5√3 or if we multiply this by √3
    (√3)x - 3y = 15

  • Trig - Reiny, Sunday, October 4, 2009 at 5:46pm

    the slope of the line is equal to the tangent of the angle that the line makes with the x-axis
    so tan(angle) = 1/√3
    angle = 30 (from the ratios of the 30-60-90 triangle)

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