 |
|
|
|
SCHOOL SUBJECTS
-
-
-
-
-
-
-
-
-
-
-
-
|
|
|
GRADE LEVELS
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
|
|
|
|
Post a New Question | Current Questions | Chat With Live Tutors
Homework Help Forum: Trig
Posted by Sarah on Sunday, October 4, 2009 at 5:29pm.
|
A line goes through points (23,-3) and (83,3). Find the equation of the line through these 2 points and the angle of incline (between the line and the x-axis).
|
- Trig - Reiny, Sunday, October 4, 2009 at 5:44pm
The slope of your line is 6/(6√3) = 1/√3
Then, using the point (2√3,-3)
y+3 = (1/√3)(x-2√3)
cross-multiplying, expanding and then simplifying I got
x - (√3)y = 5√3 or if we multiply this by √3
(√3)x - 3y = 15
|
- Trig - Reiny, Sunday, October 4, 2009 at 5:46pm
the slope of the line is equal to the tangent of the angle that the line makes with the x-axis
so tan(angle) = 1/√3
angle = 30 (from the ratios of the 30-60-90 triangle)
|
Answer this Question
|
|
|
 |