Posted by **Shayna** on Sunday, October 4, 2009 at 5:24pm.

The Yankee Clipper leaves the pier at 9:00 am at 8 knots. A half hour later the River Rover leaves the same peir going in the same direction traveling at 10 knots. At what time will the River Rover overtake the Yankee Clipper?

Please help me solve this using the d=rt formula and write an equation.

- math -
**MathMate**, Sunday, October 4, 2009 at 5:56pm
Arithmetic:

Clipper's lead = 8 knots * (1/2) hour = 4 nautical miles

For each hour, the Rover catches up by (10-8)=2 nautical miles.

Time required to catch up = 4/2 hours (after 9:30)

Time the Rover will catch up = 11:30

Algebra:

Let t=time (as of 9:30) to catch up

10*t - 8*t = 8*(1/2)

2t = 4

t=2

The Rover will catch up at 11:30.

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