Posted by **Zoe** on Sunday, October 4, 2009 at 4:31pm.

Assume it takes 6.00 minutes to fill a 45.0 gal gasoline tank. (1 U.S. gal = 231 in.3)

I don't know how to solve for part C.

(a) Calculate the rate at which the tank is filled in gallons per second.

ANSWER: 0.125

(b) Calculate the rate at which the tank is filled in cubic meters per second.

ANSWER: 4.73e-4

(c) Determine the time interval, in hours, required to fill a 1 m3 volume at the same rate.

- Physics -
**DrBob222**, Sunday, October 4, 2009 at 4:52pm
Your answer from part b is rate = ??m^{3}/s

??m^{3}/sec x sec = m^{3}

Solve for sec.

Then convert sec to hours.

sec x (1 min/60 sec) x (1 hr/60 min) = ??

- Physics -
**Zoe**, Sunday, October 4, 2009 at 5:31pm
Your answer from part b is rate = ??m3/s

??m3/sec x sec = m3

Solve for sec.

Then convert sec to hours.

sec x (1 min/60 sec) x (1 hr/60 min) = ??

---------------

So I have the rate 4.73e-4 m3/s. I'm not sure how the cancellation for the m3 to disappear, but I get the converting the second to hours part, just not the step prior to get there?

- Physics -
**DrBob222**, Sunday, October 4, 2009 at 5:36pm
rate = meter*meter*meter/seconds x seconds = meter*meter*meter. The second in the denominator of the first part cancels with second in the numerator of the second part. This is just like

(meter/second) x second = meter

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