Physics
posted by Zoe on .
Assume it takes 6.00 minutes to fill a 45.0 gal gasoline tank. (1 U.S. gal = 231 in.3)
I don't know how to solve for part C.
(a) Calculate the rate at which the tank is filled in gallons per second.
ANSWER: 0.125
(b) Calculate the rate at which the tank is filled in cubic meters per second.
ANSWER: 4.73e4
(c) Determine the time interval, in hours, required to fill a 1 m3 volume at the same rate.

Your answer from part b is rate = ??m^{3}/s
??m^{3}/sec x sec = m^{3}
Solve for sec.
Then convert sec to hours.
sec x (1 min/60 sec) x (1 hr/60 min) = ?? 
Your answer from part b is rate = ??m3/s
??m3/sec x sec = m3
Solve for sec.
Then convert sec to hours.
sec x (1 min/60 sec) x (1 hr/60 min) = ??

So I have the rate 4.73e4 m3/s. I'm not sure how the cancellation for the m3 to disappear, but I get the converting the second to hours part, just not the step prior to get there? 
rate = meter*meter*meter/seconds x seconds = meter*meter*meter. The second in the denominator of the first part cancels with second in the numerator of the second part. This is just like
(meter/second) x second = meter