Posted by Anonymous on Sunday, October 4, 2009 at 1:03pm.
Draw the triangle of vectors, ABC, where
AB represents the river velocity, 0.6 m/s due east, BC is the canoe velocity, 0.49 m/s due south-east.
You are looking for the resultant vector AC.
You can solve this by the law of cosines, which is
AC²=AB²+BC²-2AB.BC.cos(135°)
or by summing components along the x- and y-axes (East and north).
Resultant:
x-component=0.6+0.49cos(-45°) m/s
y-component=0.49sin(-45°) m/s
tan(θ)=y-component/x-component
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