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November 22, 2014

Homework Help: chemistry (drbob222)

Posted by Anonymous on Sunday, October 4, 2009 at 3:07am.

[Ni(NH3)m(H2O)p]^2+ + mHCl ->mCl- + pH2O + Ni^2+ + mNH4^+

excess HCl + OH- -> H2O

A .185 g sample of nickel salt was dissolved in 30.00 mL of 0.1013 N HCl. The excess HCl required 6.30 mL of 0.1262 N NaOH to reach the end point. Calculate the weight of the salt that contains one mole of NH3 (that is the equivalent weight of the salt)

work:
moles of ammonium in sample:
(6.30x10^-3)(.1262)
weight of salt that contains one mole of NH3: 0.185/(6.30x10^-3)(.1262)

Propose a molecular formula for the salt in 3 that is consistent with this experimental equivalent weight.

I don't know if I did the first problem correctly. I'm not sure how to do the second problem (proposing the molecular formula - the hint the teacher gave us is that the sum of m and p is less than or equal to 6 and also bromine atoms will need to be mentioned). Thanks in advance for the help!

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