At what altitude above the Earth's surface would your weight be three-fourths of what it is at the Earth's surface? Assume re = 6.371 10^3 km.
Physics - MathMate, Saturday, October 3, 2009 at 11:26am
Based on Newton's law of universal gravitation,
which means that the weight would be inversely proportional to the square of the distance from the centre of the Earth.
If H is the altitude when the weight becomes 3/4 of what's on the surface, then
Solve for H.
Physics - Lindsey, Tuesday, October 2, 2012 at 12:29am
Solved out for H:
(6371/sqrt(3/4)) - 6371 = H
for other fractions just plug in where 3/4's is.
Hope this helps!