Calculate the percentage by mass of nitrogen in PtCl2(NH3)2...can anyone help me.??
Look up or calculate the molar mass of PtCl2(NH3)2.
%N = [(2 x atomic mass N)/(molar mass compound)]*100
Sure, I can help you with that. To calculate the percentage by mass of nitrogen in PtCl2(NH3)2, we need to determine the molar mass of nitrogen and the molar mass of the entire compound.
The molar mass of nitrogen (N) is approximately 14.01 g/mol.
To calculate the molar mass of PtCl2(NH3)2, we need to consider the individual elements present in the compound:
Pt: Molar mass = 195.08 g/mol
Cl: Molar mass = 35.45 g/mol
N: Molar mass = 14.01 g/mol
H: Molar mass = 1.01 g/mol
Now let's calculate the molar mass of the compound:
(1 * Pt) + (2 * Cl) + (2 * (N + 3 * H))
= (1 * 195.08 g/mol) + (2 * 35.45 g/mol) + (2 * (14.01 g/mol + 3 * 1.01 g/mol))
= 195.08 g/mol + 70.90 g/mol + 38.08 g/mol
= 304.06 g/mol
Now, to find the percentage by mass of nitrogen, we can use the following formula:
Percentage by mass = (Molar mass of nitrogen / Molar mass of the compound) * 100
= (14.01 g/mol / 304.06 g/mol) * 100
= 4.6%
Therefore, the percentage by mass of nitrogen in PtCl2(NH3)2 is approximately 4.6%.
To calculate the percentage by mass of nitrogen in PtCl2(NH3)2, you need to first determine the molecular weight of the compound.
Let's break down the compound into its individual components and calculate their molecular weights:
Pt: The atomic mass of platinum (Pt) is approximately 195.08 g/mol.
Cl2: Chlorine (Cl) has an atomic mass of approximately 35.45 g/mol, so two Cl atoms would be 2 * 35.45 = 70.90 g/mol.
(NH3)2: Ammonia (NH3) consists of nitrogen (N) and hydrogen (H). The atomic mass of nitrogen is approximately 14.01 g/mol, and the atomic mass of hydrogen is approximately 1.01 g/mol. Since there are two ammonia molecules, the molecular weight of (NH3)2 would be 2 * [(14.01 g/mol) + (3 * 1.01 g/mol)]
Now, let's calculate the total molecular weight of PtCl2(NH3)2:
Total molecular weight = molecular weight of Pt + molecular weight of Cl2 + molecular weight of (NH3)2
Total molecular weight = 195.08 g/mol + 70.90 g/mol + 2 * [(14.01 g/mol) + (3 * 1.01 g/mol)]
Now, calculate the molecular weight of nitrogen (N) in PtCl2(NH3)2:
Molecular weight of Nitrogen (N) = 2 * [(14.01 g/mol) + (3 * 1.01 g/mol)]
Finally, calculate the percentage by mass of nitrogen in PtCl2(NH3)2:
Percentage by mass of Nitrogen = (Molecular weight of Nitrogen / Total molecular weight) * 100
Substitute the calculated values into the formula to find the answer.
Pt: about 195 g/mol
if I'm not mistaken..