Posted by **NONO** on Friday, October 2, 2009 at 10:16pm.

DURING THE FIRST PART OF A TRIP, A CANOEIST TRAVELS 35 MILES AT A CERTAIN SPEED. THE CANOEIST TRAVELS 17 MILES ON THE SECOND PART OF THE TRIP AT A SPEED OF 5 MPH SLOWER. THE TOTAL TIME FOR THE TRIP IS 3 HRS. WHAT WAS THE SPEED ON EACH PART OF THE TRIP?

- ALGEBRA -
**drwls**, Friday, October 2, 2009 at 11:07pm
Please turn off you caps lock if you post questions here again.

For this problem, let V be the speed during the first 35 miles. The speed will then be V-5 during the last 17 miles.

The time spent at each speed equals distance divided by velocity at that time. The total time is 3 hours. Therefore:

35/V + 17/(V-5) = 3

Solve that equation for V

## Answer This Question

## Related Questions

- Algebra - During the first part of a trip, a canoeist travels 98 miles at a ...
- Algebra - During the first part of a trip, a canoeist travels 57 miles at a ...
- algebra - Can someoe please help me figure this out? During the first part of a ...
- algebra - during the first part of a trip a canoeist travels 64 miles at a ...
- algebra - During the first part of a trip, a canoeist travels 69 miles at a ...
- algebra 2 - During the first part of a trip a canoeist travels 26 miles at a ...
- algebra - During the first part of a trip, a canoeist travels 69 miles at a ...
- Math - During the first part of a trip, a canoeist travels 33 miles at a certain...
- MAT117 - During the first part of a trip, a canoeist travels 68 miles at a ...
- math - During the first part of a trip, a canoeist travels 93 miles at a certain...

More Related Questions