Posted by **Kristina** on Friday, October 2, 2009 at 4:55pm.

A golfer rides in a golf cart at an average speed of 3.10 m/s for 21.0 s. She then gets out of the cart and starts walking at an average speed of 1.60 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 2.10 m/s?

I need help solving for T. I dont understand how to do it since there is a T on both sides of the problem

## Answer This Question

## Related Questions

- PHYSICS - A golfer rides in a golf cart at an average speed of 3.93 m/s for 43.3...
- physics - A golfer rides in a golf cart at an average speed of 3.93 m/s for 43.3...
- physics - A golfer rides in a golf cart at an average speed of 3.10 m/s for 28.0...
- physics - A golfer rides in a golf cart at an average speed of 3.10 m/s for 29.0...
- Physics - A golfer rides in a golf cart at an average speed of 3.10 m/s for 23.0...
- physics - A golfer rides in a golf cart at an average speed of 3.10 m/s for 26.0...
- Physics - A golfer rides in a golf cart at an average speed of 3.10 m/s for 21.0...
- Physics - A golfer rides in a golf cart at an average speed of 3.93 m/s for 43.3...
- college physics - a golfer rides in a golf cart at an average speed of 3.10 ...
- Physics - The distance time graph shows a cart moving at a straight path. a. ...

More Related Questions