Posted by **Kristina** on Friday, October 2, 2009 at 4:47pm.

A golfer rides in a golf cart at an average speed of 3.10 m/s for 21.0 s. She then gets out of the cart and starts walking at an average speed of 1.60 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 2.10 m/s?

- Physics -
**drwls**, Friday, October 2, 2009 at 4:50pm
Require that

2.10 (T+21) = 3.1*21 + 1.6*T

= (total distance travelled)

Then solve for T, which will be in seconds.

- Physics -
**Kristina**, Friday, October 2, 2009 at 4:54pm
I need help solving for T!!!

- Physics -
**bobpursley**, Friday, October 2, 2009 at 5:03pm
2.10(T+21)=3.1*21+1.6T

What kind of help do you need in solving for T?

- Physics -
**drwls**, Friday, October 2, 2009 at 5:05pm
2.1T + 44.1 = 65.1 + 1.6 T

0.5 T = 21

Can you complete the solution?

One should learn algebra before studying physics

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