Calculate the final concentration if 4.0 L of 1.5 M NaCl and 2.0 L of 3.0 M NaCl are mixed
1 Calculate the total number of moles of NaCl.
4.0 L x 1.5 mol L^-1 = 6.0 mol
2.0 L x 3.0 mol L^-1 = 6.0 mol
so total = 12.0 mol
2. Total volume = 6.0 L
3. New concentration = moles/volume
which I'll leave for you to do.
To calculate the final concentration of NaCl when two solutions are mixed, we can use the formula:
C1V1 + C2V2 = CFVF
where C1 is the initial concentration of solution 1, V1 is the initial volume of solution 1, C2 is the initial concentration of solution 2, V2 is the initial volume of solution 2, CF is the final concentration, and VF is the final volume.
In this case, we have two solutions: Solution 1 with a concentration of 1.5 M and a volume of 4.0 L, and Solution 2 with a concentration of 3.0 M and a volume of 2.0 L.
Using the formula, we can calculate the final concentration:
(1.5 M)(4.0 L) + (3.0 M)(2.0 L) = CFVF
6.0 + 6.0 = CFVF
12.0 = CFVF
To find the final concentration, we divide both sides of the equation by the final volume:
12.0 ÷ (4.0 L + 2.0 L) = CF
12.0 ÷ 6.0 L = CF
CF = 2.0 M
Therefore, the final concentration of NaCl when 4.0 L of 1.5 M NaCl and 2.0 L of 3.0 M NaCl are mixed is 2.0 M.