Posted by Jenny on Thursday, October 1, 2009 at 7:48pm.
Do you have any idea what these answers are? Or at least the approach you might take? Just giving away three answers is not my style.
I know, and i'm sorry. I am having a lot of trouble with these ones.
I thought for the second one. it would cause a higher molarity since the pH was lower, but i'm still not sure
and wouldn't the last one remain unchanged since it was at the end of the experiment and wouldn't affect it?
1). Adding NaOH to the buret after rinsing the buret with distilled water (essentially saying that you don't rinse the buret with NaOH)means that the NaOH is more dilute so it will take more NaOH from the buret to reach the equivalence point. So more mL means mL x M = a greater number which will do ?????? for the M of the vinegar?
b)Using an indicator that changes around 5 instead of about 9 will mean you must add more NaOH to get the pH to move from 5 to 9. More mL NaOH, means more M x mL = more moles NaOH and that will do what to the M of the vinegar?
c) I don't know how to answer this one because I don't understand the question. Does pushing the bubble in after the lab started mean extra NaOH was pushed out? Or does it mean something different? I don't know.
1.) wouldn't it make the molarity less
2.) then that would make the vinegars molarity higher, right?
1.) wouldn't it make the molarity less
I don't see it that way.
mLNaOH x M NaOH = mLv x Mv so
Mv = mLNaOH x M NaOH/mLv.
Increasing mL NaOH increases the numerator, mL v in the denominator stays the same so the M of the vinegar must increase.
2.) then that would make the vinegars molarity higher, right?
Same answer for the same reason.
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