Posted by **tai** on Thursday, October 1, 2009 at 5:28pm.

the 6th grade has 5 days to sell tickets to a talent show. The students predict that each day they will sell 10 fewer tickets than the day before. How many must they sell on the first day if they want to sell 200 tickets?

--- do I divide 10 by 200 that would not make sense

please try to help me thanks

- math -
**Reiny**, Thursday, October 1, 2009 at 5:34pm
You are probably studying arithmetic sequences and series

let the first term be a

common difference is -10

and the number of terms is 5

S_{n} = (n/2)[2a + (n-1)d]

200 = (5/2)[2a + 4(-10)]

400 = 5[2a - 40]

400 = 10a - 200

600 = 10a

a = 60

So on the first day they must sell 60 tickets

check: 60 + 50 + 40 + 30 + 20 =

- math -
**M Bhatt**, Thursday, October 1, 2009 at 10:59pm
assume that they will sell x tickets on the first day.

Sale on second day will be x-10

third day x-20

fourth day x-30

fifth day x-40

if we add them all up

x+x-10+x-20+x-30+x-40=200

5x-100=2==

5x=300

x=60

so they have to sell 60 on the first day

50 on the second

40 on the third

30 on the fourth

and 20 on fifth day.

- math -
**arny**, Thursday, October 8, 2009 at 12:50am
find the difference using model subtraction with renaming

- math -
**Magic**, Saturday, October 10, 2009 at 10:56am
The product of a number and seven increased by twenty-three is equal to one hundred seven.

- math -
**quandariusmoran**, Friday, October 23, 2009 at 11:40am
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