A 21.6-kg box rests on a table. A 19.3-kg box is placed on top of the first box, as shown. Determine the total force in N that the boxes exert on the table.
FIND f=ma for both and add them up?
a=9.8 gravity rite?
The force exerted on the table is the total of the masses in kg multiplied by g=9.8 m/s². The result is in N.
To determine the total force exerted by the boxes on the table, we need to calculate the individual forces exerted by each box and then add them together.
The force exerted by an object can be calculated using Newton's second law, which states that the force (F) is equal to the mass (m) of the object multiplied by its acceleration (a). In this case, the acceleration considered is the acceleration due to gravity.
Given:
- Mass of the first box (m1) = 21.6 kg
- Mass of the second box (m2) = 19.3 kg
- Acceleration due to gravity (a) = 9.8 m/s^2
First, let's calculate the force exerted by the first box:
F1 = m1 * a
F1 = 21.6 kg * 9.8 m/s^2
F1 ≈ 211.68 N
Next, calculate the force exerted by the second box:
F2 = m2 * a
F2 = 19.3 kg * 9.8 m/s^2
F2 ≈ 189.14 N
Finally, we add the forces together to determine the total force exerted by the boxes on the table:
Total force = F1 + F2
Total force ≈ 211.68 N + 189.14 N
Total force ≈ 400.82 N
Therefore, the total force exerted by the boxes on the table is approximately 400.82 Newtons (N).