Saturday

November 29, 2014

November 29, 2014

Posted by **Marina** on Thursday, October 1, 2009 at 2:50pm.

m = m0 / sqrt(1-v^2 / c^2)

where m0 is mass of the particle at rest and c is the speed of light. What happens as v approaches c^-?

- calculus - limits -
**bobpursley**, Thursday, October 1, 2009 at 3:02pmmass is unbounded, it increases. Since this cannot happen, velocity cannot equal the speed of light.

**Answer this Question**

**Related Questions**

Calculus - I don't understand this question. Q. In the theory of relativity, the...

math - In the theory of relativity, the mass of a particle with velocity v is m=...

Math - n the theory of relativity, the mass of a particle with speed v is m=f(v...

modern physics - relativity - A photon of energy E collides with a stationary ...

special relativity - A photon of energy E collides with a stationary particle ...

Physics - A particle with m = 3.3E-27 kg is moving with a velocity of 6.0E7m/s. ...

physics £££ - according to einstein's mass energy relation M= m'/root[1-(v^2/c^2...

Physics - A system consists of two particles. Particle 1 with mass 2.0 kg is ...

Physics - A system consists of two particles. Particle 1 with mass 2.0 kg is ...

physics - A proton (mass=1.67*10^-27 kg) moves with a velocity of 6.00*10^6 m/...