Posted by **Marina** on Thursday, October 1, 2009 at 2:50pm.

In the theory of relativity, the mass of a particle with velocity v is

m = m0 / sqrt(1-v^2 / c^2)

where m0 is mass of the particle at rest and c is the speed of light. What happens as v approaches c^-?

## Answer this Question

## Related Questions

- Calculus - I don't understand this question. Q. In the theory of relativity, the...
- math - In the theory of relativity, the mass of a particle with velocity v is m=...
- modern physics - relativity - A photon of energy E collides with a stationary ...
- Math - n the theory of relativity, the mass of a particle with speed v is m=f(v...
- special relativity - A photon of energy E collides with a stationary particle ...
- Physics - A particle of mass =6.50 kg moves with a velocity v1=x1i+y1j+z1k. A ...
- Physics - A particle with m = 3.3E-27 kg is moving with a velocity of 6.0E7m/s. ...
- physics - Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, ...
- physics emergerncyy! - A particle of mass m1 = 2.5 kg moving along the x axis ...
- physics - Two particles, with identical positive charges and a separation of 2....

More Related Questions