Posted by **Mario** on Thursday, October 1, 2009 at 11:32am.

A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the box on the plank and gradually raises one end of the plank. When the angle of inclination with the horizontal reaches 30°, the box starts to slip, and it slides 2.2 m down the plank in 4.4 s at constant acceleration.

(a) What is the coefficient of static friction?

(b) What is the coefficient of kinetic friction?

- Physics -
**drwls**, Thursday, October 1, 2009 at 12:03pm
(a) Let s be the coefficient of statice froction and k be the coefficient of kinetic friction.

From the info on the angle at whic slidign starts,

M g sin 30 = M g s cos 30

tan 30 = s

(b) Solve for the acceleration rate a after sliding begins. It slides a distance X in time T.

a T^2/2 = X

a = 2X/T^2

Then solve for k using Newton's second law.

M a = Mg sin 30 - M g k cos 30

a/g = sin 30 - k cos 30

## Answer This Question

## Related Questions

- physics - A student wants to determine the coefficients of static friction and ...
- PHYSICS - A student wants to determine the coefficients of static friction and ...
- physics - a student wants to determine the coefficient of static friction and ...
- physics - A 5-kg crate is resting on a horizontal plank. The coeï¬ƒ- cient of ...
- physics - a 5-kg crate is resting on a horizontal plank. the coefficient of ...
- spring- physics - A 2.0-kg box rests on a plank that is inclined at an angle of ...
- Spring Physics - A 2.0 kg box rests on a plank that is inclined at an angle of ...
- physics - A 2.0kg box rests on a plank that is inclined at an angle of 65° above...
- Simmons - A 2.0 kg box rests on a plank that is inclined at an angle of 65° ...
- Physics - A m = 1.85 kg box rests on a plank that is inclined at an angle of &#...

More Related Questions