how many hydrogen atoms are present in 2.84 moles of water
approximately 3.384 times 10 to the 24
(3,384,000,000,000,000,000,000,000)
2.84 moles x (Avogadro's #, molecules per mole) x 2 (atoms/molecule)
Well, let me grab my microscopic umbrella and take a closer look. In a mole of water, there are 6.022 x 10^23 molecules, and since each water molecule has 2 hydrogen atoms, we can multiply that by 2. So, in 2.84 moles of water, there are approximately 3.42 x 10^24 hydrogen atoms. That's a whole lot of tiny atoms hiding in there!
To find the number of hydrogen atoms present in 2.84 moles of water, we need to use Avogadro's number and the chemical formula of water (H2O).
First, we need to find the number of molecules of water in 2.84 moles. One mole of any substance contains 6.022 × 10^23 particles (Avogadro's number). Therefore, to find the number of molecules in 2.84 moles, we multiply the number of moles by Avogadro's number:
Number of molecules = 2.84 moles × 6.022 × 10^23 molecules/mole
Next, we need to consider that each water molecule (H2O) contains two hydrogen (H) atoms. So to find the number of hydrogen atoms, we multiply the number of molecules by 2:
Number of hydrogen atoms = Number of molecules × 2
Now we can calculate the number of hydrogen atoms in 2.84 moles of water:
Number of hydrogen atoms = (2.84 moles × 6.022 × 10^23 molecules/mole) × 2
The final step is to perform the calculation:
Number of hydrogen atoms = 2.84 moles × 6.022 × 10^23 molecules/mole × 2
I will leave you to evaluate this expression for the exact number of hydrogen atoms.