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September 16, 2014

September 16, 2014

Posted by **Chan** on Wednesday, September 30, 2009 at 1:27am.

A.How far horizontally from the base of the building does the ball strik the ground?

B.Find the height from which the ball was thrown.

C.How long does it take the ball to reach a point 10.0m below the level of launching? Thank you so much for your help

- physic -
**drwls**, Wednesday, September 30, 2009 at 6:07amA. Multiply the horizontal component of the initial velocity by the time that the ball is in the air.

7.80 x cos 21 x 3.00 = ?

B. Solve the following equation for vertical height above the ground, for the unknown height H.

y = 0 = H -7.80 sin 21 t - (g/2) t^2

using t = 3.0 seconds. g is the acceleration of gravity, 9.8 m/s^2.

C. Use a different vertical height equation, with t as the unknown and the vertical height above the ground being

y = H -10

= H -7.80 sin 21 t - (g/2) t^2

Note that the H cancels out, leaving

-10 = -7.80 sin 21 t - (g/2) t^2

There will be two roots. Take the one that is positive

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