Posted by Anonymous on Wednesday, September 30, 2009 at 12:39am.
Given the system of inequalities below, find the vertices of the feasible region. Report your vertices starting with the one which has the smallest xvalue. If more than one vertex has the same, smallest xvalue, start with the one that has the smallest yvalue. Proceed clockwise from the first vertex.
y<x+7
y>7x+11
x>0 y> 0
if someone could explain it to me that would be wonderful!

math  Anonymous, Wednesday, September 30, 2009 at 12:45am
where did you get 10?

math  Shavaleir, Wednesday, September 30, 2009 at 12:52am
x and y equals 10

math  MathMate, Thursday, October 1, 2009 at 8:23am
y<x+7
y>7x+11
x>0 y> 0
Graphically, draw the four inequalities as through they are lines,
y=x+7
y=7x+11
x=0
y= 0
They should intersect at six distinct points.
Create the figure that represents the region of feasibility.
The goal is to find the boundaries of the region of feasibility bounded by four intersection points, and the correspoinding segments of straight line representing the inequalities.
This can be achieved (as described in the question) by starting at the origin (intersection of x>0 and y>0) and proceeding along the xaxis to the next intersection point. If this point satisfies all constraints, or at the border of it, proceed along the straight line. If not, go back to the previous point and continue with the intersecting line.
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