Posted by **Some kid** on Tuesday, September 29, 2009 at 11:54pm.

Suppose f(x) is the function 2x^3+ 12x^2+

21x + 3. Find the smallest value of f at which the tangent to the curve is 3.

I did:

f'(x)+ 6x^2+ 24x + 21= 3

= 6(x+3)(x+1), x= -3, -1

the correct answer is supposed to be -8

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