Calculate the mass of each product formed when 43.82g of diborane (B2H6) reacts with excess water:
B2H6(g) + H2O(l)--> H3BO3(s) + H2(g)
Chemistry - Ms. Sue, Tuesday, September 29, 2009 at 7:15pm
We know that all of the last chemistry problems have been posted by one person.
We might be able to help you if you keep the same name and tell us what you've done to try and answer these questions.
Chemistry - DrBob222, Tuesday, September 29, 2009 at 7:34pm
See my earlier response.